A 0.05kg bullet travelling at 500ms-1 horizontally strikes a thick vertical wall. It stops after...

JAMB 1985

A 0.05kg bullet travelling at 500ms^-1 horizontally strikes a thick vertical wall. It stops after penetrating through the wall horizontal distance of 0.25m. What is the magnitude of the average force the wall exerts on the bullet?

A. 25N
B. 50N
C. 250N
D. 500N
E. 25 000N

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Correct Answer: Option E

Explanation

F = ma

= m\(\frac{(v^2 - u^2)}{2s}\)

F = 0.05\(\frac{(0 - (500)^2)}{2 \times 0.25}\)

F = 25 000N

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A 0.05kg bullet travelling at 500ms-1 horizontally strikes a thick vertical wall. It stops after...

Correct Answer: Option E

Explanation

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