Physics
JAMB 1985
A simple pendulum with a period of 2.0s has its length doubled. Its new period is
-
A.
1.00s
-
B.
1.41s
-
C.
0.3s
-
D.
2.83s
-
E.
4.00s
Correct Answer: Option D
Explanation
Using \(\frac{T_1}{T_2}\) = \(\sqrt\frac{L_1}{L_2}\)
\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)
T2 = 2.83sec
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}