A 1000kg elevator is descending vertically with an acceleration of 1.0ms-2, if the acceleration due to gravity is 10ms-2, the tension in the suspending cable is

olyezema

4 years ago

It is descending not ascending so you have to minus a from g
F=M(g - a)
F=1000(10 - 1)
F= 9000N

Deedon19

3 years ago

T=M(g-a)
M=1000kg
a=1m/s
g=10m/s
- sign due to descending

T=1000(10-1)
T=1000*9
T=9000N

lordnewton

5 years ago

wrong when moving downwards the body doesnt press down with more force
it should be g-a

Acetabulum

5 years ago

Downward acceleration
T=mg-ma
g is greater than a
T=1000(10-1)
T=9000N @myschool
Pls make corrections

Bboyz

8 years ago

Its descending so total acceleration shuld b 10-1=9

GreatEgnrOpemipo

5 months ago

It is sending so G is greater

RHODES

10 years ago

you didnt give us total acceleration as 11

damarischimdinmaokafor

2 years ago

No explanation on how to solve it correctly?

emma_0_0_8

1 year ago

when moving down or descending you are under the influence of gravity in addition to your acceleration same thing as in a lift
that being said it should be M(g+a)= 11,000

precious_gift

9 years ago

Tension = W + F

W = mg

= 1000kg × 10m/s2

= 10000N

F = ma

= 1000 × 1

= 1000N

Tension = 10000N + 1000N

= 11000N