A galvanometer of resistance 20\(\Omega\) is to be provided with a shunt that \(\frac{1}{10}\) of the whole current in a circuit passes through the galvanometer. The resistance of the shunt is
a
2.00\(\Omega\)
b
2.22\(\Omega\)
c
18.00\(\Omega\)
d
18.22\(\Omega\)
Explanation
Correct Option
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Olajumokejohn
1 year ago
The voltage through the shunt and the galvanômetro must be the same and since the current passing through the galvanometer is 1/10 of the whole current then the remaining current passing through the shunt is 9/10 of it thus
IR for galvanômetro = IR for shunt
Rg/10 = 9Rs/10
20/10 = 9Rs/10
2*10 = 9Rs
Rs = 20/9
Rs = 2.22ohms
