The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 150Hz?

a

1

b

2

c

3

d

4

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Explanation

Correct Option
b

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Discussions (11)

christy1234
9 years ago

the right answer is B

okenyichinonso
4 years ago

In a string the overtones are both odd and even multiples, it's only in a pipe closed at one ends that you have only odd multiples

teebreezy101
7 years ago

In a string it is fo=v/2l

f1=2fo=2*40=80

f2=3fo=3*40=120

f3=4fo=4*40=160
ANSWER IS B

christy1234
9 years ago

in a string it is fo=v/2l

f1=2fo=2*40=80

f2=3fo=3*40=120

f3=4fo=4*40=160

Sensei
2 months ago

correct 2 ☹️😘

olyezema
4 years ago

Pls it was not indicated if it was a close pipe so why do you solve using it formula.............
Fundamental frequency/first harmonic=v/2l
1st Overtone/2d harmonic =2×f
2nd overtone/3rd harmonic=3×f.

Dorcas7777
2 months ago

I don't understand it

Tompep
1 year ago

neg 1st

peter samson
9 years ago

please explain

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