The length of a side of a metallic cube at 20ºC is 5.0cm. Given that the linear expansivity of the metal is 4.0 x 10\(^{-5}\)k\(^{-1}\), find the volume of the cube at 120°C.
Recall that: Volume = L * L * L → 5 * 5 * 5 = 125
Y = \(\frac{V_2 - V_1}{V_1 \times \theta}\)
3 x 4 x 10\(^{-5}\) = \(\frac{V_2 - 125}{125 \times (120 - 20)}\)
V\(_2\) = 126.50cm\(^{3}\)
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