Physics
JAMB 1987
A constant force of 40N acting on a body initially at rest gives an acceleration of 0.1ms
-2 for 4s. Calculate the work done by the force
-
A.
8J
-
B.
10J
-
C.
32J
-
D.
160J
Correct Answer: Option C
Explanation
X = ut + \(\frac{1}{2}\)at2
= (0 x 4) + (\(\frac{1}{2}\) x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J
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