A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. The efficiency of the cell is
a
12.0%
b
25.0%
c
33.3%
d
75.0%
Explanation
Correct Option
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Redhawk
2 years ago
r is internal resistance
R is external resistance or resistor
R=2
r=6
e of cell = Ir/I(R+r) * 100%
I cancel each other
r
-- * 100%
R+r
input it and get your freaking answer


