A force, 10N, drags a mass 10kg on a horizontal table with an acceleration of 0.2ms. If the acceleration due to gravity is 10ms-1, the coefficient of friction between the moving mass and the table is
a
0.02
b
0.08
c
0.20
d
0.80
Explanation
Correct Option
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Discussions (11)
Ay17
7 years ago
The selected answer is wrong it shud be B
F -Fr = umg
where F is applied force
fr is d frictional force
Fr = ma
F - ma = umg
10 - 10 × 0.2 = 10 × 10× u
8 = 100u
u = 0.08
therefore d correct ans is B
I stand to be corrected if am wrong
Azpi
5 years ago
I think that the frictional force has been wrongly calculated. It should be the pulling force-ma. That would give 8N. Hence, correct answer should be B(0.08)
