A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s^-1, the angular speed of the larger wheel is

3 rev s^-1

40 rev s^-1

360 rev s^-1

2400 rev s^-1

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otikpaceejay

10 years ago

absolutely wrong

the greater the number of teeth,the smaller the speed..the bigger one has 60/20=3 times more teeth so it has a speed 3times smaller of 120/3=40rev/s (B)

Godhild

4 years ago

Some text missed this calculation.
pls note 40rev/s is the correct answer

Divineonehi

4 years ago

This question is about gear ratio
Gear ratio = Output speed /input speed
Also
Gear ratio = No. of teeth of driving wheel/No. of teeth of driven wheel
So equating it we have
Output speed/input speed =No of teeth of driving wheel/No of teeth of driven wheel
So from the question we have
Output speed/120revs=20/60
Output speed=20/60 *120
Output speed= 40revs.
So the answer is B .My School this should be corrected

agadido

3 years ago

number of tooth is inversely proportional to angular speed, so @Myschool kelly what happened?

OsagieN

2 years ago

𝟰𝟬 𝐫𝐚𝐝/𝐬 𝐁

Bt1

2 years ago

the 20 tooth is turning at 120 rev/sec, and the driven gear has 60 tooth, the rotational speed of the driven gear would be:
V= NL/Ns= Ws//wl
NL= number tooth for large gear
Ns= number of tooth for small gear
Wl= angular velocity for large gear
Ws= Angular velocity for small gear
120 rev/sec * (20/60) = 120 rev/sed* (1/3) = 40 rev/sec

option B is the most viable option for me