Three resistors, with substances 250\(\Omega\), 500\(\Omega\) and 1k\(\Omega\) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250\(\Omega\) resistor.
a
0.20V
b
0.86V
c
1.71V
d
3.43V
Explanation
Correct Option
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joystina
5 years ago
Three resistors in series =250+500+100=1750
From V=IR
6=Ix1750
I=3.4x10^-3
P. D at the end of 250ohms
V=IR
V=3.4x10^-3X250
=0.857volts.
