Physics
JAMB 1989
Three resistors, with substances 250\(\Omega\), 500\(\Omega\) and 1k\(\Omega\) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250\(\Omega\) resistor.
-
A.
0.20V
-
B.
0.86V
-
C.
1.71V
-
D.
3.43V
Correct Answer: Option B
Explanation
Using voltage - divider method
v1 = \(\frac{(R_1)}{R_T}\)VT
= \(\frac{250}{1750}\) x \(\frac{6}{1}\)
= 0.86V
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}