A vibrator of frequency 60Hz is used in generating transverse stationary waves in a long thin wire, If the average distance between successive nodes on the wire is 45cm, find the speed of the transverse waves in the wire.
27ms-1
54ms-1
90ms-1
108ms-1
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (16)
Speed =force × distance × of two successive nodes
S=60 ×0.45 × 2 successive nodes
S=27×2; successive nodes
S=54 ms-1
The question was distance between successive nodes
F=v/2l
l=45/100=0.45m
v=60×2×0.45
v=54m/s
or
Speed (v) = Wavelength (λ) x Frequency (f)
First, we need to find the wavelength (λ). Since the average distance between successive nodes is half the wavelength, we can write:
λ = 2 x distance between nodes
= 2 x 45 cm
= 90 cm
= 0.9 m
Now, we can plug in the values:
v = λ x f
= 0.9 m x 60 Hz
= 54 m/s
Therefore, the speed of the transverse wave in the wire is 54 m/s.
very correct sir the answer is meant to be 54 = 2 * the distance between two successive nodes
guys lets go 🤗🤗🤗
V=2F(L2-L1)
v=?
F=60Hz
L2-L1(average length) =45cm, to m 45/100=0.45m
v=2×60(0.45)
120×0.45=54m/s
