A substance has a half of 3mins. after 6mins. the count rate was observed to be 400. What was its count rate at zero time?

Didi2005

4 years ago

3 = 1/2x = x
6= 1/4×= 400
but
1/4x = 400
x= 4*400 = 1600
×= 1600

kairakizitor7

1 year ago

gather here if you think the answer was 200 😭😭😭😭🥇

Ibrahim fatimoh

9 years ago

Explanation pls

B3cca

2 years ago

Question is not phrased properly. It's confusing

PrinceJohn489

1 year ago

We know that the substance has a half-life (t1/2) of 3 minutes. This means that every 3 minutes, the count rate (or activity) decreases by half.

We're given that after 6 minutes, the count rate is 400. We need to find the initial count rate at time 0.

Since 6 minutes is equal to two half-lives (3 minutes x 2), we can use the following formula:

Initial count rate = Final count rate x 2^(Number of half-lives)

Plugging in the values, we get:

Initial count rate = 400 x 2^(2)
= 400 x 4
= 1600

Therefore, the count rate at time 0 was 1600.