A sonometer wire of length 100cm under a tension of 10N, has a frequency of 250Hz. Keeping the length of the wire constant, the tension is adjusted to produce a new frequency of 350Hz. The new tension is

Anela

1 year ago

F1/F2 = √T2/√T1

F1=250
F2=350
T1=10
T2=?

250/350 = √10/√T2
square both sides to take off the √ sqr. root sign

62500/122500 = 10/T2
CROSS MULTIPLY ✖️

122500×10 = 62500T2
1225000=62500T2

T2=1225000/62500
=19.6

Akabeke

1 year ago

please a detailed explanation

kairakizitor7

1 year ago

first 😭🥇

Emex_ooo

1 year ago

The frequency varies directly as the square root of tension. Apply variation to get the constant and it gives that formula which is used in the question