A light wave of frequency 5 x 10\(^{14}\)Hz moves through water which has a refractive index of \(\frac{4}{3}\). Calculate the wavelength in water if the velocity of light in air is 3 x 10\(^8\)ms\(^{-1}\)

FAECSB7610542

1 year ago

Wrong explanation. Pls check

Precociousone

4 years ago

It's supposed to be:
Refractive index=v1/v2=f1l1/f2l2=l1/l2
Where l is lamda which is wavelength.
4/3=3*10^8/v=6*10^-7/l
4/3= 6*10^-7/l
l=(3*6*10^-7)/4
l=4.5*10^-7m.
Where v1 is 3 x 10^8, refractive index is 4/3

Dhavi

2 years ago

We were asked to calculate wavelength of water
But we were not given wavelength of light
To get wavelength of light we use
lambda=velocity of light/frequency of light
lambda= 3× 10^8/5×10^14
lambda= 0.45×10^-6 or 4.5×10 ^-7

benrt09

2 months ago

Is it not 2.5x10⁸ that would be v that means Lamda is equal to v/f = 2.510⁸/5x10-¹⁴, which would give 5x10-⁸