A car moving with a speed of 90kmh-1 was brought uniformly to rest by the application of the brakes in 10s. How far did the car travel after the brakes were applied?
speed = \(\frac{90 \times 10^3}{3600}\) = 25ms-1
Acceleration = velocity change / time = 25 / 10
: Acceleration = 2.5
Using S = Ut + \(\frac{1}{2}\) at^2
S = \(\frac{1}{2}\) X 2.5 X 10^2 = 125m
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