A moving coil galvanometer of 300\(\Omega\) resistance gives full scale deflection for 1.0mA. The resistance R, of the shunt that is required to convert the galvanometer into a 3.0A ammeter is

Faozydayo

5 years ago

ig rg=isrs
300*0.001=3rs
rs=0.3/3
0.10ohms

Bazile

6 years ago

Ig Rg = Is Rs
1.0mA= 0.001A
300×0.001÷3
=0.10ohms

Heyitharyor

4 years ago

This, i think is the right solution
IsRs = IgRg
Is = 3 - Ig
=3-(1/1000)
= 2.999A
2.999 * Rs = 0.001 * 300
Rs = 0.100ohms