A trough 12.0cm deep is filled with water of refractive index \(\frac{4}{3}\). By how much would a coin at the bottom of the trough appear to be displaced when viewed vertically from above the water surface?

a

3.0cm

b

6.0cm

c

9.0cm

d

16.0cm

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Correct Option
a

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Discussions (6)

Dave333
4 years ago

🤦So you will substract it again,Lord have mercy upon me 🙏

Oluwaseyimercy123
2 months ago

They got 9 by using cross multiply

Ezomoolivia
3 years ago

pls how did they get 9 here my calculator says 16 oo pls can someone explain 🙏

Peter9695
3 years ago
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The answer should have been 4cm

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