A brass rod is 2m long at a certain temperature. What is the length for a temperature rise of 100K, if the expansivity of brass is 18 x 10^-6K^-1?

Adakue77

4 years ago

∆L =alpha × original length × ∆T
=( 18×10^-6 1/k) (× 2) ×(100k)
=3.6^-03m or 0.0036m
=2m+ 0.0036m
=2.0036m

Debbypebby

4 years ago

Write answer but wrong use of formula @ myschool
The right formula should be
L2=L1(1+a©)
L2=2 (1+0.000018*100)
L2=2.0036m.

Shikina

Viktorkipling

4 years ago

wrong answer 0.0036 not 2.0036

Parkzih

2 years ago

By definition, the gain in length will be:



Δ
�
=
�
�
0
Δ
�
ΔL=αL
0

ΔT
where
�
=
18
×
1
0
−
6
�
−
1
α=18×10
−6
K
−1
is the expansivity,
�
0
=
2
�
L
0

=2m is the initial length, and
Δ
�
=
100
�
ΔT=100K is the change in temperature. Thus, obtain:



Δ
�
=
18
×
1
0
−
6
⋅
2
⋅
100
=
3.6
×
1
0
−
3
=
0.0036
�
ΔL=18×10
−6
⋅2⋅100=3.6×10
−3
=0.0036m
Hence, the final length will be:



�
=
�
0
+
Δ
�
=
2
�
+
0.0036
�
=
2.0036
�
L=L
0

+ΔL=2m+0.0036m=2.0036m
Answer. 2.0036m.

Aaronmillzzz

2 months ago

the answer was not in the option
it was supposed to be 2.00036

sammyOGWO

3 years ago

actually some people learn things not just copying street person

Viktorkipling

4 years ago

Answer is 0.0036m not 2.0036m

Viktorkipling

4 years ago

all you do is copy answers from other websites without confirming the process......spits....pathetic