A body of weight W N rest on a smooth plane inclined at an angle\(\theta\)o to the horizontal. What is the resolved part of the weight in Newtons along the plane?
W sin\(\theta\)
W cos\(\theta\)
W sec\(\theta\)
W tan\(\theta\)
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (12)
To solve this problem, we need to resolve the weight W of the body into components acting along the inclined plane.
Formula:
The weight of the body, W, acts vertically downward. Since the plane is inclined at an angle θ to the horizontal, the weight can be resolved into two components:
- A component *along the plane* (parallel to the plane).
- A component *perpendicular to the plane*.
The resolved part of the weight along the plane is given by:
W_along = W ·sinθ
Where:
- W_along is the component of the weight along the plane.
- W is the total weight of the body (in Newtons).
- θ is the angle of inclination of the plane with the horizontal.
Conclusion:
The resolved part of the weight along the plane is W ·sinθ.
This is the answer you’re looking for.
A is correct.
Weight acts vertically downwards so we will go for the vertical resolution which is Wsintheta✅🙃
