An element X of an atomic number 88 and mass number 226 decays to form an element Z by emitting two beta particles and an alpha particle. Z is represented by
a
\(^{222}_{82}Z\)
b
\(^{222}_{88}Z\)
c
\(^{226}_{86}Z\)
d
\(^{226}_{80}Z\)
Explanation
Correct Option
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Longman101
11 years ago
Please,, who solve dix questn? This is a social media that is TRUSTED by NIGERIANS
