The terminal voltage of a battery is 4.0V when supplying a current of 2.0A, and 2.0V when supplying a current of 3.0A. The internal resistance of the battery is

Anzyumoh

3 years ago

Terminal voltage E = IR +ir, or I(R+r)
which means E = V+v
in the first case V is give as 4(from V=IR) where R is the external resistance, I=2,but r(internal resistance) was not given?...., that means E=4+2r.....eqn(i)
same in de second. V=2, I=3, r=?....
E=2+3r....eqn(ii)
equating both terminal voltage eqn to be E=E
4+2r=2+3r
collect like terms
r=2..
It's simple don't mind the bulk explanation...

Chokmahwisdomoche

2 years ago

V=4v. V=2v
I=2A. I=3A
And we are ask to find internal resistance (r)
Since E=I(R+r). E=IR+Ir
Therefore we can deduce from E=E
To be IR+Ir=IR+IR
But V=IR
So we have. V+Ir=V+IR
Substituting for numbers we have
4+2r=2+3r
4-2=3r-2r
2=r
r=2

Queenpatriarch

10 years ago

please any one with a better explanation should help please

missie

10 years ago

e=v+ir

Maximum2025

6 months ago

So emf is constant(The same in both supplies)i.e E=E.

El.vis

4 years ago

Someone should explain 🙏🙏