Two forces of magnitudes 7N and 3N act at right angles to each other. The angle \(\theta\) between the resultant and the 7N force is given by
cos\(\theta\) = \(\frac{3}{7}\)
sin\(\theta\) = \(\frac{3}{7}\)
tan\(\theta\) = \(\frac{3}{7}\)
cot\(\theta\) = \(\frac{3}{7}\)
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (5)
7N force acts horizontally, and the 3N force acts vertically.
Because they’re at right angles, we can apply Pythagoras to find the resultant.
R = √(7² + 3²) = √(49 + 9) = √58
But wait... we don’t actually need the magnitude of R to solve this.
We’re finding the angle θ between the 7N force and the resultant.
Adjacent = 7N
Opposite = 3N
Resultant = hypotenuse
So, the angle θ is between the adjacent (7N) and hypotenuse (resultant).
To find angle θ, we use this identity:
cosθ = adjacent / hypotenuse
But we don’t have the hypotenuse... so let’s try another identity. 
Let’s use: tanθ = opposite / adjacent
So: tanθ = 3 / 7 
And boom!
That’s the answer! (C)
The selected answer is wrong:
Given that the 2 forces are at right angle to each other, the angle to be calculated is between the force 7 and the resultant. Resolving it, you'll get tantita=3/7
Find by means of vector diagrams the resultant of two force 7n and 3n perpendicular to each other
