A certain radioisotope of \(^{235}_{92}U\) emits four alpha particles and three beta particles. The mass number and the atomic number of the resulting elements respectively are

Chidera2107

1 year ago

let this humble one explain

an alpha particle is a helium particle . which has an atomic number of 2 and a mass number of four
hence the (4\2)

So the equation looks like this
U235/92 = 4(4/2) 3(0/-1)

4 is from the four alpha particles in the question
3 is from the three beta particle also in the questions
any questions ? no? good .


then for the alpha particles =( 4* 2) + (3*-1) the ones under times the number outside the brackets cos the atomic number is written below.
our ans is 8*-3 =5
92-5 =87
the same for the mass number (4*4) + (3*0)
=16+0=16
=235-16=219


therefore the ans is U219/87
your welcome
you can call me shizun
muahahahah

Chiko2006

3 years ago

More explanation is needed for this question, please my school.

Aloma777

2 years ago

Where are the figures coming from????🧐

Chimbuchi20

3 years ago

i dont understand please

jasperokoh

1 year ago

I dont understand either, not even a bit