An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.

De sage

1 year ago

d= t(n-1)/n
where d= displacement
n= refractive index
t= thickness
d= 3(1.5-1)/1.5
d=3×0.5/1.5
d=1.5/1.5
d=1

MsughJoshua

4 years ago

we are comprehending

Dave333

4 years ago

What the,that was close🤦

auntytowobola

7 years ago

we are not given apparent displacement

Johnny95

6 years ago

d=t(1-1/n)
d=3(1-1/1.5)
d=3(0.5/1.5)
d=3(0.333)
d=0.999~1cm