decreased
increased
unchanged
oscillating
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Discussions (9)

Answer: Opt B
Solution
METHOD 1*
The higher the center of gravity of a body the higher the potential energy
Conversely The lower the center of gravity the lower the potential energy
*So... A cone in an unstable equilibrium will have the highest center of gravity (highest potential energy)*
Hence.. the potential energy is increased from from zero to maximum
Opt B
*METHOD 2*
P.e= mgh
From the above expression,,, p.e is directly proportional to height,,,
I.e
P.e~h
Let the p.e and height
At stable EQUILIBRIUM be p.e₁ and h₁
also the p.e and height in an unstable equilibrium be p.e₂ and h₂
So...
h₂>h₁
Dat means
p.e₂>p.e₁
This follows that potential energy at p.e₂ is increased from p.e₁
Hence... Opt B
*METHOD 3*
_Law of conservation of energy_
We said energy is transferred from one form to another... We can also say that energy is transferred from *a higher potential to a lower potential*
Okay... If the cone is in an unstable equilibrium,, when it receive a small force it will do more work (more energy)
Compared to when it's in a stable EQUILIBRIUM
Hence,, the energy is *increased* from stable to unstable equilibrium
Hence... Opt B

It has its pe decreased since pe z d energy pozezd by a body by virtue of its position

Option b is correct. My school is right on this one.
https://www.quora.com/What-happens-to-the-potential-energy-of-the-stable-and-unstable-equilibrium-when-slightly-displaced


