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An electric current of 2 amperes flows in a heating coil of resistance 50 ohms...

Physics
JAMB 1995

An electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced
  • A. 0.5kJ
  • B. 8.0kJ
  • C. 20.0kJ
  • D. 40.0kJ
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Correct Answer: Option D
Explanation
Heat energy = Elect. energy


heat energy= I2RT

= 2 X 2 X 50 X 200

= 40000J

to convert to kJ, divide J by 1000

hence, \(\frac{40000}{1000}\) = 40kJ

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