An electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced

trilz

9 years ago

(3×60)+20=200

ChinecheremAnyaoha

10 years ago

the answer is not there. the correct answer is 364kj

Atere Jr

10 years ago

u should already know that they meant 3 minutes and not 30. That was how they artived at the answer 40kj.

elviso

10 years ago

exactly... Therez a mistake in d question

emeraldknytt

10 years ago

The question is wrongly composed:

Shouldn't 30mins be equal to (30X60)secs which in turn is equivalent to 1800secs plus the 20secs which eventually gives 1820secs. I have a feeling the answer isn't in the options given.

Bukason.

11 years ago

what? how did u get 200 pls? it shud be (30x60)+20 secs=1820secs