A rectangular metal block of volume 10\(^{-6}\)m\(^3\) at 273k is heated to 573k. If its coefficient of linear expansion is 1.2 x 10\(^{-5}\)k\(^{-1}\), the percentage change of it volume is
Y = \(\frac{\Delta V}{V \times \Delta \theta}\)
3 x 10-5 x 1.2 = \(\frac{\Delta\ V}{10^{-6}\times\ (573 - 273)}\)
\(\Delta\)V = 1.080 x 10\(^{-7}\)m\(^3\)
%\(\Delta\)V = \(\frac{1.080 \times\ 10^{-7}}{10^{-6}}\) x 100
= 1.08%
\(\approx\) = 1.1%
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