A hydraulic press has a large circular piston of radius 0.8m and a circular plunger of radius 0.2m. A force of 500N is exerted by the plunger. Find the force exerted on the piston

aanu96

5 years ago

The answer is 8000N i just solved it myself.

Evanzdgenius

9 years ago

pressure plunger =force/area(22/7*radius squre)

500/3.142x0.2x0.2

=500/0.12568

pressure of piston= force/area

force/3.142x0.8x0.8

force/2.01088

Now, p. piston= p.plunger

force /2.01088 = 500/0.12568

CROSS MULTIPLY

force of piston =8000N

Kendan23

4 years ago

I got 31.25 ooooooooo
Can someone explain to me how una get 8000n

Greatestt

7 years ago

MySchool the answer is 8000N for goodness sake!!!
U guyz didnt even follow the question in your working.

dannyyor

7 years ago

The ans. is 8000N. A small amount of force is used to generate a large amount of force so as to compress the obj.

hiflows

9 years ago

Its 8000N naw

olyezema

4 years ago

Hydraulic press=
F1/A1=F2/A2
500/0.2²π=F2/0.8²π
F2=500×0.64π/0.04π
F2=8000N
F2=500×0.64/0.04
F2=8000N

aanu96

5 years ago

Hydraulic press works on the principle of pascal's law
P=
a
1
​

F
1
​

​
=
a
2
​

F
2
​

​

Omejeb

8 years ago

The correct answer is 31N.because pie will cancel pie.