A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 x 10³km, g = 10ms^-2]

Deepthinker581

4 years ago

V=√2gr
Where v is escape velocity
Convert the radius of the earth to meter
I.e 6.4×10³km to meter
= 6.4×10³×1000m
g=10ms-²
V=√2×10×6.4×10³×1000
V=√128000000
V=11313.7085ms-¹

MERCYOLADEPO

1 year ago

the formula and solution is not corresponding with the answer??????????