The voltage of the domestic electric supply is represented by the equation V = 311 sin314.2t. Determine the frequency of the a.c. supply [\(\pi\) = 3.142]
50.0Hz
100.0Hz
311.0Hz
314.2Hz
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velocity in A.C ... V = Vo Sin 2 pie ft
Compare V = 311 Sin 314.2t
2pief = 314.2
f= 314.2/2pie, f= 314.2/2(3.142) = 314.2/6.284
= 50Hz

V=vosinwt: V=311sin314.2t
w=2Īf. find f (neglect t)
w/2Ī=f (Ī=3.14)
314.2/2*3.14=50Hz

To determine the frequency of the a.c. supply, we need to analyze the given equation representing the voltage of the domestic electric supply:
V = 311 sin 314.2t
In this equation, the argument of the sine function is 314.2t, where t represents time.
The angular frequency (Ī) is the coefficient of t in the argument of the sine function. In this case, Ī = 314.2 rad/s.
The relationship between angular frequency (Ī) and frequency (f) is given by:
Ī = 2Īf
Substituting Ī = 314.2 rad/s and solving for f, we get:
314.2 = 2Ī Ã f
f = 314.2 / (2Ī)
f = 50.0 Hz
Therefore, the frequency of the a.c. supply is 50.0 Hz.
The correct answer is A. 50.0 Hz.


