A galvanometer of internal resistance 50\(\Omega\) has a full scale deflection for a current of 5mA. What is the resistance required to covert it to a voltmeter with full scale deflection of 10V?

Dave333

4 years ago

🖥️

Oghenemaroregan

1 year ago

R = V/I -R
v=10 I=5/1000 =0.005 R=50
10/0.005 -50
=1950ohms

Annabel

2 months ago

R=(V/I_g)-G
where V=volt
I_g =deflection of current
G=internal resistance substitute the values don't forget mA =10-³ and in this question it's 5×10-³

victoresin

4 years ago

Dora
Formula for converting galvanometer to voltmeter=Rm=V-IR/Im
Where Rm=resistance of multiplayer
V=potential difference
I=current
R=internal resistance
Im=current flowing through multiplayer
Just sustitute the value and there u go😉

Okosg

5 years ago

pls can someone expalin this question

Pttyu

4 months ago

E =i(R+r) where E = 10 .and i =0.005.
10/0.005 =R+50
2000= R+50
so therefore R =1950 .