its pressure decreases
the total momentum of its molecules remains constant
its pressure decreases and the total momentum of its moleculees remains constant
its pressure decreses and the total kinetic energy of its molecule decreases
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In an isothermal process, when a gas expands at constant temperature, the **total kinetic energy** of the gas molecules remains constant since kinetic energy is related to temperature. Given that temperature is constant, the kinetic energy — and consequently the total momentum — of the gas molecules remains constant.
Thus, the correct answer is **C. its pressure decreases and the total momentum of its molecules remains constant**.
This is because:
- **Pressure decreases** due to the expansion (Boyle's Law: \( P \propto \frac{1}{V} \)).
- **The total momentum of the molecules remains constant** since the temperature, and hence the average kinetic energy, does not change.
They are right
Boyle's law explains it all
P is inversely proportion to the volume provided temp remains constant
When a gas expands at a constant temperature, its pressure decreases because the gas molecules spread out over a larger area. However, the total momentum of the gas molecules remains constant during this process. This is because the individual speeds and directions of the molecules may change, but the overall momentum of the system stays the same. So, even though the pressure drops, the total momentum of the gas molecules doesn't change. Therefore the answer is C
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...𝗣𝗿𝗲𝘀𝘀𝘀𝘂𝗿𝗲 𝗱𝗲𝗰𝗿𝗲𝗮𝘀𝗲𝘀. 𝗧𝗵𝗲 𝘁𝗼𝘁𝗮𝗹 𝗺𝗼𝗺𝗲𝗻𝘁𝘂𝗺 𝗼𝗳 𝘁𝗵𝗲 𝗴𝗮𝘀 𝗺𝗼𝗹𝗲𝗰𝘂𝗹𝗲𝘀 𝗿𝗲𝗺𝗮𝗶𝗻𝘀 𝗰𝗼𝗻𝘀𝘁𝗮𝗻𝘁 𝗯𝗲𝗰𝗮𝘂𝘀𝗲 𝗺𝗼𝗺𝗲𝗻𝘁𝘂𝗺 𝗶𝘀 𝘁𝗵𝗲 𝗽𝗿𝗼𝗱𝘂𝗰𝘁 𝗼𝗳 𝗺𝗮𝘀𝘀 𝗮𝗻𝗱 𝘃𝗲𝗹𝗼𝗰𝗶𝘁𝘆, 𝗮𝗻𝗱 𝗻𝗲𝗶𝘁𝗵𝗲𝗿 𝗼𝗳 𝘁𝗵𝗲𝘀𝗲 𝗳𝗮𝗰𝘁𝗼𝗿𝘀 𝗰𝗵𝗮𝗻𝗴𝗲 𝗱𝘂𝗿𝗶𝗻𝗴 𝗲𝘅𝗽𝗮𝗻𝘀𝗶𝗼𝗻. 𝗧𝗵𝗲 𝗶𝗻𝗱𝗶𝘃𝗶𝗱𝘂𝗮𝗹 𝗺𝗼𝗹𝗲𝗰𝘂𝗹𝗲𝘀 𝗺𝗶𝗴𝗵𝘁 𝗰𝗵𝗮𝗻𝗴𝗲 𝘁𝗵𝗲𝗶𝗿 𝘃𝗲𝗹𝗼𝗰𝗶𝘁𝗶𝗲𝘀, 𝗯𝘂𝘁 𝘁𝗵𝗲 𝘀𝘂𝗺 𝗼𝗳 𝘁𝗵𝗲𝗶𝗿 𝗺𝗼𝗺𝗲𝗻𝘁𝗮 𝗿𝗲𝗺𝗮𝗶𝗻𝘀 𝗰𝗼𝗻𝘀𝘁𝗮𝗻𝘁.
The answer is opt D
When the gas expands we mean that its volume increases at constant temperature (charles law)
Now,,, the gases are widely separated from each other following the inverse squared law,,, we see that its kinetic energy must have decrease as well as its pressure owing to the relationship,,, v~¹/p
