Before starting a journey, the tyre pressure of a car was 3 x 10⁵Nm^-2 at 27^oC. At the end of the journey, the pressure rose to 4 x 10⁵Nm^-2. Calculate the temperature of the tyre after the journey, assuming the volume is constant

Award

3 years ago

P1= 300,000
T1 (27+273)= 300K
P2 = 400,000
T2 = ?
P1÷T1 = P2÷T2
making T2 subject of the formula
T2 = P2×T1÷ P1
T2 = 400,000 × 300 ÷ 300,000
T2 = 400k
But the answer is in °C
Therefore 400 - 273 = 127°C
MY SCHOOL IS VERY CORRECT ✅✅

Bumb

4 years ago

how did you get 4*10^6 when the question says 4*10^5

Bumb

4 years ago

wrong answer ,the correct answer is A

Iamkingsley23

8 months ago

My schoolcbt is correct, @dave chnge from c to k

mexfrancis

10 years ago

The selected answer is wrong:

T2 wil be p2*t1/P1 dt gves 400 degree

REF: general phsics text book

Dave333

4 years ago

Just take a look at the mistake,my school did,it 3x10^6,And 4x10^6.please my school verify this

Dave333

4 years ago

I don't really understand,How did they got 400k