Physics
JAMB 1997
An arrow of mass 0.1kg moving with a horizontal velocity of 15ms
-1 is shot into a wooden block of mass 0.4kg lying at rest on a smooth horizontal surface. Their common velocity after impact is
-
A.
15.0 ms-1
-
B.
7.5 ms-1
-
C.
3.8 ms-1
-
D.
3.0 ms-1
Correct Answer: Option D
Explanation
M1U1 + M2U2
= (m1 + m2)v
= \(\frac{(0.1 {\times} 15) + (0.4 {\times} 0)}{(0.1 + 0.4)}\)
v = 3ms-1
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