A 5kg block is released from rest on a smooth plane inclined at an angle...

JAMB 1997

A 5kg block is released from rest on a smooth plane inclined at an angle of 30^o to the horizontal. What is the acceleration down the plane? [g = 10ms^-2]

A. 5.0 ms^-2
B. 5.8 ms^-2
C. 8.7 ms^-2
D. 25.0 ms^-2

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Correct Answer: Option A

Explanation

ma = mgsin\(\theta\)

a = \(\frac{5 {\times} 10 {\times} sin30}{t}\)

a = 5ms²

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A 5kg block is released from rest on a smooth plane inclined at an angle...

Correct Answer: Option A

Explanation

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