In a resonance tube experiment, if the fundamental frequency of the vibrating air column is 280Hz, the frequency of the third overtone is

Classicboymoses

4 years ago

They are correct, resonance tube is a closed pipe
The overturn in closed system are progressively odd numbers unlike open system where they progress arithmetically.

Closed pipe
1st overturn = 3rd harmonic

2nd overturn = 5th harmonic

3rd overturn = 7th harmonic

4th overturn = 9th harmonic

The question was for the 3rd overturn
3rdO. = 7x280

3rdO. = 1960hz

But for open pipe it progresses arithmetically
1st Overturn = 2nd Harmonic

2nd overturn = 3rd harmonic

3rd overturn = 4th harmonic etc

So D is correct ✍️👽

Greatestt

7 years ago

How?

kairakizitor7

1 year ago

ai said it's D

adepojuisaiah

5 years ago

correct

kairakizitor7

1 year ago

TF BRO 😭💔

Achieverlight

1 year ago

My school the answer is C not D
coz the F3=4f
f³= 4×280= 1120
Even Google AI and chartgpt confirmed it. so please do correction

Deepthinker581

4 years ago

F¹=280
F³=5
2×280=840
5×280==1400

840-1400
=1120hz
Beta still
4×280=1120Hz