In a wheel and axle mechanism the diameters of the wheel and axle are 40cm and 8cm respectively. Given that the machine is 80% efficient, what effort is required to lift a load of 100N?

fabamz01

3 months ago

You can solve it gradually by finding V.R first
which is

VR=diameter or radius of wheel /diameter or radius of axle

VR=40/8
VR=5

Then, u will find MA to get your effort
Eff= MA*100/VR

80= MA*100/5

cross multiply

100MA= 80*5
MA=400/100
MA= 4

MA=load/effort

4= 100/e
4e= 100
e=100/4

e=25N

.

Myschool Kelly

9 years ago

The question has been modified. Thanks for your observation.

Chimemeria

9 years ago

that tin suppose to be 8cm not 80cm.....my school Kelly,cum adjust your question