The force of attraction between two point masses is 10^-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.

imani200

2 years ago

my school is very correct ...the formula to use is newton law of universal gravitational formula . in this case we are not making use of the two Masses cus it wasn't given .... remember force of attraction between two mass is is directly proportional to product of the mass and inversely to the square of the distance between them

F~ 1/ r²

F x r ² ..... formula 1

F2 x r²2 .….. formula 2

formula 1 = formula 2

F x r² = F2 x r²2

0.0001 x (0.18)² = F x (0.06)²

F= 0.0001 x (0.18)² / (0.06)²

F= 0.0009 N = 9 x 10–⁴ N

Lowiza

7 years ago

The answer is 1.1×10^-5
From the formula
F1\F2=r12/r22
10^-4/F2 =0.18^2
----------
0.06^2
Cross multiply and make F2 subject of formula
F2=10^-4 ×3.6×10^-3
-----------------------
3.24×10^-2
=3.6×10^-7
-------------
3.24×10^-2
=1.1×10^-5 final answer

AlwaysLucky

4 months ago

ok