A conductor of length 1m moves with a velocity of 50ms^-1 at an angle of 30^o to the direction of a uniform magnetic field of flux density 1.5Wbm^-2. What is the e.m.f induced in the conductor?

Araluchinechelum

4 years ago

E=qvsin@
E=1.5×50sin30
E=37.5

Chikem55

4 years ago

F= BVLsin-0-

Emmanayobami

4 years ago

pls help solve this

Princeransome01

2 months ago

Let's calculate the induced emf

Using the equation: ε = Blv sin(θ)

- B = 1.5 Wb/m²
- l = 1 m
- v = 50 m/s
- θ = 30°

ε = 1.5 × 1 × 50 × sin(30°)
ε = 1.5 × 50 × 0.5
ε = 37.5 V

Induced emf is 37.5 V

Annur27

1 year ago

Thanks