A particle carrying a charge of 1. 0 x 10-8C enters a magnetic field at...

JAMB 2012

A particle carrying a charge of 1. 0 x 10^-8C enters a magnetic field at 3.0x 10^-2 ms ^-1 at right angles to the field. If the force on this particle is 1.8 x 10^-8N, what is the magnitude of the field?

A. 6.0x10^-1T
B. 6.0x10T
C. 6.0x10^-3T
D. 6.0x10^-4T

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Correct Answer: Option B

Explanation

F = BQV

B = \(\frac{F}{QV}\)

B = \(\frac{1.8 \times 10^{-8}}{1.0 \times 10^{-8} \times 3.0 \times 10^{-2}}\)

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A particle carrying a charge of 1. 0 x 10-8C enters a magnetic field at...

Correct Answer: Option B

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