The equation of a wave traveling in a horizontal direction is expressed as y = 15 sin \(\frac{2\pi}{5}\) (60t - x). What is its wavelength?

Nwese

5 years ago

I kn that the is write ooo, but ur question is wrong, the correct question is 15 sin2pie/ 5(60t-x),

marlianlawa

2 years ago

The answer is 15.7, you were given your k from the equation "y=Asin(2pift-kx)" and k=(2*pi)/wavelength.

treasurecoliver

3 years ago

am just confused
i thought the t
fraction is to be multplied before equating the formula
i got 15cm

leoflex

10 years ago

NICE QUESTION LIKE IT SERIOUSLY

KEEP UP THE GOOD WORK

shezvictorious

3 years ago

pls u need an explanation on that .
its kind of confusing

Nwese

5 years ago

I kn that the is write ooo, but ur question is wrong, the correct question is 15 sin2pie/ 5(60t-x)

DominicAfam

1 year ago

There is error in this question

OSCA123

1 year ago

@myschool pls answer

OSCA123

11 months ago

it is wrong

Gddhhcv

2 years ago

I'm confused 😓

mercy12345678ush

2 years ago

H

Wawaaaaaaaaaaaqa

2 years ago

wave length should be 5pie not 5 or 15.7m no option is correct

AyanfeOba.Dudu

1 year ago

We’re given the wave equation:

𝑦
=
15
sin
⁡
(
2
5
(
60
𝑡
−
𝑥
)
)
y=15sin(
5
2
​
(60t−x))
This matches the general form of a traveling wave:

𝑦
=
𝐴
sin
⁡
(
𝜔
𝑡
−
𝑘
𝑥
)
y=Asin(ωt−kx)
Where:

𝐴
A is amplitude (15 in this case),

𝜔
ω is angular frequency,

𝑘
k is the wave number,

𝑥
x is position,

𝑡
t is time.

From the equation:

2
5
(
60
𝑡
−
𝑥
)
=
2
5
⋅
60
𝑡
−
2
5
𝑥
=
24
𝑡
−
2
5
𝑥
5
2
​
(60t−x)=
5
2
​
⋅60t−
5
2
​
x=24t−
5
2
​
x
So, comparing with
𝜔
𝑡
−
𝑘
𝑥
ωt−kx:

𝜔
=
24
ω=24

𝑘
=
2
5
k=
5
2
​


Now use the formula for wavelength:

𝜆
=
2
𝜋
𝑘
λ=
k
2π
​

Substitute
𝑘
=
2
5
k=
5
2
​
:

𝜆
=
2
𝜋
2
5
=
2
𝜋
⋅
5
2
=
5
𝜋
≈
15.7
 
m
λ=
5
2
​

2π
​
=2π⋅
2
5
​
=5π≈15.7m
Among the options, the closest is:

Correct Answer: B. 15 m