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The equation of a wave traveling in a horizontal direction is expressed as y =...

Physics
JAMB 2012

The equation of a wave traveling in a horizontal direction is expressed as y = 15 sin \(\frac{2\pi}{5}\) (60t - x). What is its wavelength?

  • A. 60m
  • B. 15m
  • C. 5m
  • D. 2m
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Correct Answer: Option C
Explanation

Given: y = 15 sin \(\frac{2\pi}{5}\) (60t - x).

comparing  y = 15 sin \(\frac{2\pi}{5}\) (60t - x) with the equation of wave motion Asin\(\frac{2\pi}{\lambda}\)(x - vt)

\(\frac{2\pi}{5}\) = \(\frac{2\pi}{\lambda}\)

Therefore, \(\lambda\) = 5m.

There is an explanation video available below.


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Explanation Video

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