A cell of emf 1.5V is connected in series with a 1Ω resistor and a current of 0.3A flows through the resistor. Find the internal resistance of the cell
a
4.0Ω
b
3.0Ω
c
1.5Ω
d
1.0Ω
Explanation
Correct Option
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sammytheeagle
9 years ago
V=I(r+R) Therefore
V=1.5
I=0.3
R=1
r=x
1.5=0.3(1+r)
1.5=0.3+0.3r
0.3r=1.5-0.3
0.3r=1.2
r=1.2/0.3
r=4
Thanks
