A ray of light passing through the centre of curvature of a concave mirror is reflected by the mirror at?
0o
45o
90o
180o
Explanation
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The answer is 180.
0 degree would mean that the ray continued moving in the same line without reflecting back.
90 degrees would mean that the ray reflected back at right angle.
180 degree would mean that the ray reflected back in the opposite direction or in the same line since it had originally hit the mirror perpendicularly at angle 90
A ray of light passing through the centre of
curvature of a concave mirror retraces its path
(gets reflected along the same path),
because as the ray of light passes through
centre of curvature of a concave mirror it
strikes the mirror along the normal i.e. it
incidences on to the mirror at 90 degree.
answer is C
As the ray of light passes through centre of curvature of a concave mirror it strikes the mirror along the normal (i.e. it incidences on to the mirror at 90 degree and 0 degree with normal).
Since it strikes the mirror at the normal then it's 0°.
The answer is A.
According to the law of reflection, when a light ray hits a surface perpendicularly, the angle of incidence is 0°, and the angle of reflection is also 0°.
As the ray of light passes through centre of curvature of a concave mirror it strikes the mirror along the normal (i.e. it incidences on to the mirror at 90 degree and 0 degree with normal).
The correct answer is C.
Technically it is 180;the direction of the reflected ray is opposite the incident ray
