Two liquids X and Y having the same mass are supplied with the same quantity of heat. If the temperature rise in X is twice that of Y, the ratio of specific heat capacity of X to that of Y is

Award0001

2 years ago

from the question, @x = 2@y
H = mc
making c subject
c = H/m@
since mass is the same c = H/@
cx = H/2@y
cy = H/@y

cx /cy = H/2@y ÷ H/@y

cx/cy = H/2@y × @y/H

cx/cy = @y/2@y = 1/2

cx/cy = 1:2

Comfort81

1 year ago

I think the answer is supposed to be A coz x =2*y and if you divide both sides by y then x/y = 2 which is 2:1. That's option A

Chimemeria

8 years ago

suppose to be option b o

ThankGodNwaoha

7 years ago

Hey d right ansa is B oo

chinexx

9 years ago

it is b

KOURT

2 months ago

Incorrect answer

teebreezy101

7 years ago

answer is B Temp(x)= 2*Temp(y)