Physics
JAMB 2013
A gas at a pressure of 10
5Nm
-2expands from 0.6m
-3 to 1.2m
3 at constant temperature, the work done is
-
A.
7.0 x 106J
-
B.
6.0 x 10 6J
-
C.
6.0 x 10 5J
-
D.
6.0 x 10 4J
Correct Answer: Option D
Explanation
W = \(\frac{W_1 \times V_1}{V_2}\)
W = \(\frac{10 \times 0.6}{1.2}\)
W = 6.0 x 10
4J
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