An object is moving with a velocity of 5m-1. At what height must a similar body be situated to have a potential energy equal in value with kinetic energy of the moving body?
A.
25.0m
B.
20.0m
C.
1.3m
D.
1.0m
Correct Answer: Option C
Explanation
P.E = K.E
Therefore, h = \(\frac{v^2}{2g} = \frac{5^2}{2 \times 10}\)
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